[FieldTrip] Symmetric Source Reconstruction
Schoffelen, J.M. (Jan Mathijs)
jan.schoffelen at donders.ru.nl
Mon Feb 6 09:40:04 CET 2017
Hi Behzad,
You could try to do the following, before calling ft_sourceinterpolate:
sourceC.pos = sourceC.pos(:,1:3);
Best,
Jan-Mathijs
J.M.Schoffelen, MD PhD
Senior Researcher, VIDI-fellow
Telephone: +31-24-3614793
Physical location: room 00.028
Donders Centre for Cognitive Neuroimaging, Nijmegen, The Netherlands
> On 26 Jan 2017, at 17:36, Behzad Iravani <behzadiravani at gmail.com> wrote:
>
>
> Dear FieldTrip experts ,
>
> I'm interested to perform symmetric source reconstruction on time lock data. However I encountered an error. here is my code:
>
> cfg = [];
> cfg.grid.unit = 'mm';
> cfg.grid.resolution = 5;
> cfg.grid.tight = 'yes';
> cfg.inwardshift = -2;
> cfg.headmodel = vol;
> cfg.symmetric ='y'; % symmetric sources
>
> grid = ft_prepare_sourcemodel(cfg);
>
>
> % timelock data for two conditions
>
> load timelockA %co-variance computed
> load timelockB %co-variance computed
> load timeloackAB %co-variance computed
>
> load elecfile.mat % sensor positions
> load vol.mat % pre-compute head model
>
> cfg = [];
> cfg.method = 'lcmv';
> cfg.grid = grid;
> cfg.headmodel = vol;
> cfg.elec = elecfile;
> cfg.keepfilter = 'yes';
> source = ft_sourceanalysis(timeloackAB); % compute common filter
>
> cfg.keepfilter = 'no';
> cfg.grid.filter =source.avg.filter
> sourceA = ft_sourceanalysis(timeloackA); % compute common filter
>
> sourceB = ft_sourceanalysis(timeloackA); % compute common filter
>
>
> % Contrast Condition A versus B
> cfg = [];
> cfg.parameter = 'pow';
> cfg.operation = '(x1./x2-1)';
> SourceC= ft_math(cfg,sourceA ,sourceB);
>
> load mri.mat % load anatomical image
>
> cfg = [];
> cfg.parameter = 'pow';
> sourcePostInt = ft_sourceinterpolate(cfg, SourceC ,mri);
>
> here I get error in ft_warp_apply because the grid.pos is 6*n which it is supposed to be 3*n, since I chose the symmetric option it turned to 6*n.
>
> How can I solve this problem?
>
> Thanks in advance
> Best
>
> Behzad
>
>
>
>
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