On Mon, 20 Nov 2000, Siegfried Gonzi wrote: > per def.: lim(n->infinity) (1 + 1/n)^n == e > > with the old 68040 Motorola they were able to use n>1.0e15, but with the 64bit and > n>1.0e15 the above formula delivers 1. In fact, the (...)^n converge to e but slowly. Taking that limit doesn't make for an effective algorithm. rthappe