Re[2]: sum, perfomance?

Valery A.Khamenya khamenya@module.ru
Tue, 6 Jun 2000 14:39:19 +0400


Hello John,

you wrote:

JvG> Yes, when StdList was written the Clean compiler could not
JvG> transform 'foldl (+) 0' into an efficient version. The current
JvG> compiler can, so it could now be defined as:  

JvG> sum l = foldl (+) zero l

what compiler version do you mean here?

-- 
Best regards,
 Valery                            mailto:khamenya@module.ru